15.2 Laplace Transform
INTRODUCTION
In Chapter 4 we defined the Laplace transform of a function f(t), t ≥ 0, to be
whenever the improper integral converges. This integral transforms a function f(t) into another function F of the transform parameter s, that is, {f(t)} = F(s). The main application of the Laplace transform in Chapter 4 was to the solution of certain types of initial-value problems involving linear ordinary differential equations with constant coefficients. Recall, the Laplace transform of such an equation reduces the ODE to an algebraic equation. In this section we are going to apply the Laplace transform to linear partial differential equations. We will see that this transform reduces a PDE to an ODE.
Transform of Partial Derivatives
The boundary-value problems considered in this section will involve either the one-dimensional wave and heat equations or slight variations of these equations. These PDEs involve an unknown function of two independent variables u(x, t), where the variable t represents time t ≥ 0. We define the Laplace transform of u(x, t) with respect to t by
where x is treated as a parameter. Throughout this section we shall assume that all the operational properties of Sections 4.2, 4.3, and 4.4 apply to functions of two variables. For example, by Theorem 4.2.2, the transform of the partial derivative ∂u/∂t is
that is, (1)
Similarly, (2)
Since we are transforming with respect to t, we further suppose that it is legitimate to interchange integration and differentiation in the transform of ∂2u/∂x2:
that is, (3)
In view of (1) and (2) we see that the Laplace transform is suited to problems with initial conditions—namely, those problems associated with the heat equation or the wave equation. We will see in Section 15.4 that boundary-value problems involving Laplace’s equation in which one (or both) of the spatial variables is defined on an unbounded interval can often be solved using different integral transforms.
EXAMPLE 1 Laplace Transform of a PDE
Find the Laplace transform of the wave equation
SOLUTION
From (2) and (3),
becomes
or (4) ≡
The Laplace transform with respect to t of either the wave equation or the heat equation eliminates that variable, and for the one-dimensional equations the transformed equations are then ordinary differential equations in the spatial variable x. In solving a transformed equation, we treat s as a parameter.
EXAMPLE 2 Using the Laplace Transform to Solve a BVP
Solve
subject to
SOLUTION
The partial differential equation is recognized as the wave equation with a = 1. From (4) and the given initial conditions, the transformed equation is
(5)
where U(x, s) = {u(x, t)}. Since the boundary conditions are functions of t, we must also find their Laplace transforms:
{u(0, t)} = U(0, s) = 0 and {u(1, t)} = U(1, s) = 0. (6)
The results in (6) are boundary conditions for the ordinary differential equation (5). Since (5) is defined over a finite interval, its complementary function is
Uc(x, s) = c1 cosh sx + c2 sinh sx.
The method of undetermined coefficients yields a particular solution
Hence
But the conditions U(0, s) = 0 and U(1, s) = 0 yield, in turn, c1 = 0 and c2 = 0. We conclude that
Therefore ≡
EXAMPLE 3 Using the Laplace Transform to Solve a BVP
A very long string is initially at rest on the nonnegative x-axis. The string is secured at x = 0, and its distant right end slides down a frictionless vertical support. The string is set in motion by letting it fall under its own weight. Find the displacement u(x, t).
SOLUTION
Since the force of gravity is taken into consideration, it can be shown that the wave equation has the form
where g is the acceleration due to gravity. The boundary and initial conditions are, respectively,
The second boundary condition lim ∂u/∂x = 0 indicates that the string is horizontal at a great distance from the left end. Now from (2) and (3),
becomes
or, in view of the initial conditions,
The transforms of the boundary conditions are
With the aid of undetermined coefficients, the general solution of the transformed equation is found to be
The boundary condition lim dU/dx = 0 implies c2 = 0, and U(0, s) = 0 gives c1 = g/s3. Therefore
Now by the second translation theorem we have
or
To interpret the solution, let us suppose t > 0 is fixed. For 0 ≤ x ≤ at, the string is the shape of a parabola passing through the points (0, 0) and (at, − gt2). For x > at, the string is described by the horizontal line u = gt2. See FIGURE 15.2.1. ≡
Observe that the problem in the next example could be solved by the procedure in Section 13.6. The Laplace transform provides an alternative solution.
EXAMPLE 4 A Solution in Terms of erf (x)
Solve the heat equation
subject to
SOLUTION
From (1) and (3) and the given initial condition,
becomes (7)
The transforms of the boundary conditions are
(8)
Since we are concerned with a finite interval on the x-axis, we choose to write the general solution of (7) as
Applying the two boundary conditions in (8) yields, respectively, . Thus
Now the inverse transform of the latter function cannot be found in most tables. However, by writing
and using the geometric series
we find
If we assume that the inverse Laplace transform can be done term by term, it follows from entry 3 of Table 15.1.1 that
(9)
The solution (9) can be rewritten in terms of the error function using erfc(x) = 1 − erf (x):
(10) ≡
Also see Problem 8 in Exercises 15.1
FIGURE 15.2.2(a), obtained with the aid of the 3D plot function in a CAS, shows the surface over the rectangular region 0 ≤ x ≤ 1, 0 ≤ t ≤ 6 defined by the partial sum S10(x, t) of the solution (10). It is apparent from the surface and the accompanying two-dimensional graphs that at a fixed value of x (the curve of intersection of a plane slicing the surface perpendicular to the x-axis) on the interval [0, 1], the temperature u(x, t) increases rapidly to a constant value as time increases. See Figure 15.2.2(b) and 15.2.2(c). For a fixed time (the curve of intersection of a plane slicing the surface perpendicular to the t-axis), the temperature u(x, t) naturally increases from 0 to 100. See Figure 15.2.2(d) and 15.2.2(e).
15.2 Exercises Answers to selected odd-numbered problems begin on page ANS-38.
In the following problems use tables as necessary.
- A string is secured to the x-axis at (0, 0) and (L, 0). Find the displacement u(x, t) if the string starts from rest in the initial position A sin(πx/L).
- Solve the boundary-value problem
- The displacement of a semi-infinite elastic string is determined from
Solve for u(x, t).
- Solve the boundary-value problem in Problem 3 when
Sketch the displacement u(x, t) for t > 1.
- In Example 3, find the displacement u(x, t) when the left end of the string at x = 0 is given an oscillatory motion described by f(t) = A sin ωt.
- The displacement u(x, t) of a string that is driven by an external force is determined from
Solve for u(x, t).
-
- A uniform elastic bar is clamped at and is initially at rest. If a constant unit force is applied to the free end at the longitudinal displacement of a cross section is determined from
Solve for [Hint: Expand in a geometric series. See Example 4.]
- For a fixed value of x satisfying sketch the graph of as a function of t for
- Sketch the graph of as a function of t for
- A uniform elastic bar is clamped at and is initially at rest. If a constant unit force is applied to the free end at the longitudinal displacement of a cross section is determined from
- A uniform semi-infinite elastic beam moving along the x-axis with a constant velocity −v0 is brought to a stop by hitting a wall at time t = 0. See FIGURE 15.2.3. The longitudinal displacement u(x, t) is determined from
Solve for u(x, t).
- Solve the boundary-value problem
- Solve the boundary-value problem
In Problems 11–18, use the Laplace transform to solve the heat equation uxx = ut, x > 0, t > 0 subject to the given conditions.
-
[Hint: Use the convolution theorem.]
- Solve the boundary-value problem
- Show that a solution of the boundary-value problem
where r is a constant, is given by
- Solve the boundary-value problem
- Solve the boundary-value problem
- A rod of length L is held at a constant temperature u0 at its ends x = 0 and x = L. If the rod’s initial temperature is u0 + u0 sin(xπ/L), solve the heat equation uxx = ut, 0 < x < L, t > 0 for the temperature u(x, t).
- If there is a heat transfer from the lateral surface of a thin wire of length L into a medium at constant temperature um, then the heat equation takes on the form
where h is a constant. Find the temperature u(x, t) if the initial temperature is a constant u0 throughout and the ends x = 0 and x = L are insulated.
- A rod of unit length is insulated at x = 0 and is kept at temperature zero at x = 1. If the initial temperature of the rod is a constant u0, solve kuxx = ut, 0 < x < 1, t > 0 for the temperature u(x, t). [Hint: Expand 1/(1 + ) in a geometric series. See Example 4.]
- An infinite porous slab of unit width is immersed in a solution of constant concentration c0. A dissolved substance in the solution diffuses into the slab. The concentration c(x, t) in the slab is determined from
where D is a constant. Solve for c(x, t).
- A very long telephone transmission line is initially at a constant potential u0. If the line is grounded at x = 0 and insulated at the distant right end, then the potential u(x, t) at a point x along the line at time t is determined from
where R, C, and G are constants known as resistance, capacitance, and conductance, respectively. Solve for u(x, t). [Hint: See Problem 7 in Exercises 15.1.]
- Show that a solution of the boundary-value problem
is
- Starting at t = 0, a concentrated load of magnitude F0 moves with a constant velocity along a semi-infinite string. In this case, the wave equation becomes
where is the Dirac delta function. Solve the above PDE subject to
when
- Solve the boundary-value problem in Problem 29 when
- The temperature in a semi-infinite solid is modeled by the boundary-value problem
where is a nonzero constant. Solve for Use the solution to determine analytically the value of
- In Problem 31, if there is a constant flux of heat into the solid at its left-hand boundary, then the boundary condition is
where is a positive constant. Solve for Use the solution to determine analytically the value of
In Problems 33–36, the partial differential equation is the heat equation in spherical coordinates
Take the Laplace transform of this PDE with respect to the variable t. To solve the transformed equation, use the substitution where
- In Problem 9 of Exercises 14.3 you were asked to find the time-dependent temperature inside a unit sphere centered at the origin. Find the temperature outside a unit sphere if the boundary and initial conditions are
- Find the temperature outside a unit sphere if the boundary and initial conditions are
where and are nonzero constants.
- Find the temperature inside a unit sphere if the boundary and initial conditions are
where and are nonzero constants.
- Find the temperature outside a unit sphere if the boundary and initial conditions are
where is a nonzero constant.
Mathematical Model
- Pulsating Sphere A sphere of radius centered at the origin is submerged in an ideal compressible fluid. Starting at the surface of the sphere is caused to pulsate with radial velocity where is a nonzero constant. The pulsation continues indefinitely. A cross section of the sphere is shown in FIGURE 15.2.4. A simplified model for the velocity potential of points in the surrounding fluid is given by the boundary-value problem
Solve for Then determine the radial velocity of points in the fluid.
- Find the radial velocity of points in the fluid surrounding the sphere of radius r = a in Problem 37 if the boundary and initial conditions are
In this case, the sphere is expanding for a period of time but is not pulsating.
Computer Lab Assignments
- Use a CAS to obtain the graph of in Problem 31 over the rectangular region defined by Assume and Indicate the two boundary conditions and initial condition on your graph. Use 2D and 3D plots of to verify the value of
- Use a CAS to obtain the graph of in Problem 32 over the rectangular region defined by Assume and Use 2D and 3D plots of to verify the value of
- Chemical Messages Humans gather most of their information on the outside world through sight and sound. But many creatures use chemical signals as their primary means of communication; for example, honeybees, when alarmed, emit a substance and fan their wings feverishly to relay the warning signal to the bees that attend to the queen. These molecular messages between members of the same species are called pheromones. The signals may be carried by moving air or water or by a diffusion process in which the random movement of gas molecules transports the chemical away from its source. FIGURE 15.2.5 shows an ant emitting an alarm chemical into the still air of a tunnel. If c(x, t) denotes the concentration of the chemical x centimeters from the source at time t, then c(x, t) satisfies
and k is a positive constant. The emission of pheromones as a discrete pulse gives rise to a boundary condition of the form
where δ(t) is the Dirac delta function.
- Solve the boundary-value problem if it is further known that c(x, 0) = 0, x > 0, and lim c(x, t) = 0, t > 0.
- Use a CAS to plot the graph of the solution in part (a) for x > 0 at the fixed times t = 0.1, t = 0.5, t = 1, t = 2, t = 5.
- For a fixed time t, show that (x, t) dx = Ak. Thus Ak represents the total amount of chemical discharged.